IF Q is the midpoint of PR, find the coordinates of R if P(11,-2) and Q(4,3). Write your answer in (x, y) format.

The coordinates of R is (-3,8)

Step-by-step explanation:

The formula for the midpoint of a line segment is;

(x,y) = (x1 + x2)/2, (y1 + y2)/2

In this case, we have (x,y) = (4,3)

and we also have (x1,y1) = (11,-2)

what we do not have is (x2,y2)

From the question, we have that;

(11 + x2)/2 = 4

11 + x2 = 2(4)

11 + x2 = 8

x2 = 8-11

x2 = -3

Also;

(-2 + y2)/2 = 3

-2 + y2 = 2(3)

-2 + y2 = 6

y2 = 6 + 2

y2 = 8

So the coordinates of R is (-3,8)

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.