Damarcus and Xavier went to the arcade to play their two favorite games. Damarcus played 4 rounds of game 1 and 6 rounds of game 2 for $18.00. Xavier played 5 rounds of each game for $20. What is the cost of game 1? A. $1.00 B. $2.00 C. $3.00 D. $4.00

The correct option is (c).

Step-by-step explanation:

Let x and y denote the cost of game 1 and game 2 respectively.

ATQ,

4x+6y = 18  (1)

5x + 5y = 20 (2)

Multiply equation (1) by 5 and equation (2) by 4.

20x+30y = 90 (3)

20x + 20y = 80 (4)

Subtracting equation (3) and (4)

20x+30y - (20x + 20y) = 90-80

20x-20x+30y-20y = 10

10y = 10

y = 1

Put the value of y in equation (1).

4x+6(1) = 18

4x = 18-6

4x = 12

x = 3

Hence, the cost of game 1 is $3.00