The half-life of a certain radioactive substance is 14 days. There are 6.6 grams of the substance present initially. Which equation represents the number of grams of the radioactive substance
on day 42?

A(t) = 0.825 g

Step-by-step explanation:

To solve this for amount remaining, we will use the equation;

A(t) = A_o × (½)^(t/t_½)

We are given;

Initial amount; A_o = 6.6 g

Half life; t_½ = 14

Time elapsed; t = 42

A(t) is amount of substance remaining

Thus;

A(t) = 6.6 × (1/2)^(42/14)

A(t) = 6.6 × (1/2)³

A(t) = 6.6 × ⅛

A(t) = 0.825 g

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it would take 7/10 of an hour too fill the pool.

step-by-step explanation: