Suppose six students from the class are chosen at random what is the probability none are mechanical engineering majors

Complete question :

In a class of 125 students, 27 are computer science majors, 51 are mechanical engineering majors, 12 are civil engineers and the rest are general engineering majors. Assume students only have one major.

Suppose six students from the class are chosen at random what is the probability none are mechanical engineering majors?

0.039

Step-by-step explanation:

Total = T = 125

Computer Science = S = 27

Mechanical Engineering = M = 51

Civil Engineering = C = 12

General engineering, G = 125 - (27 + 51 + 12) = 35

Probability that none out of six chosen at random are Mechanical Engineering major :

Probability = required outcome / Total possible outcomes

Non mechanical engineering majors = 125 - 51 = 74

Probability none of 6 selected are mechanical engineering majors :

74C6 / 125C6

Recall :

nCr = n! / (n-r)! r!

, using calculator :

74C6 / 125C6 = 185250786 / 4690625500

= 0.0394938

= 0.039

p = 6s

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.