Divide. Enter the answer in simplest form. 2 1/7 divided by 2/7
__/7 divided by 2/7
__/7 x __/__ = ___

the answer is 4 1/2

Step-by-step explanation:

first you have to turn your 2 1/7 into an improper fraction :  2x1+7, and you get 9/7.

then you divide 9/7 by 2/7 or you can also flip the second fraction and multiply : 9/7 divided by 2/7 turns into --- 9/7 x 7/2 so from here you cross simplify, you cant simplify 2 into 9 so no simplifying there but 7 can go into 7 once so you are left with 9/1 and 1/2 then multiply 9x1 and 1x2 and you get 9/2.

from here you turn your improper fraction into a proper fraction by seeing how many times 2 can go into 9 , which is 4 times (4 is the whole numbers) and you are left with 1 (numerator) over 2 (denominator)

two data sets with the same median will not have the same varaibility

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!