A line passes through (6, 3), (8, 4), and (n, -2). Find the value of n.

n = -4

because the line (d) passes through (6;3) and (8;4)

=> (d): passes through (6;3)

          the normal vector n(1; -2)

=> (d): x - 6 - 2(y - 3) = 0

=> (d): x - 2y = 0

because d also passes through (n; -2)

=> n - 2.(-2) = 0

⇔ n + 4 = 0

⇔ n = -4

Step-by-step explanation:

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: