A coin toss bet is placed between two friends such that the person who wins four tosses first is the winner. What is the total number of possible ways in which the bet can play out

who wins four tosses first is the winner.

possible cases-7 tosses, 6 tosses, 5 tosses, 4 tosses

We get cases of Win of Head first-4 tosses

All 4 must be Head

Number of ways = 1

5 tosses-5th must be Head  

there are 3 Head   out of 4  in  ⁴C₃ = 4 Ways

6 tosses-6th must be Head  

there are 3 Head  out of 5  in  ⁵C₃ = 10 Ways

7 tosses-7th must be Head  

there are 3 Head   out of 6  in  ⁶C₃ = 20 Ways

Cases of Head wins = 1+ 4 + 10 + 20  = 35

similarly cases when  Tails Wins = 35

Total Possible cases = 35 + 35 = 70

70 is total number of possible ways in which the bet can play out.

Step-by-step explanation:

I hope that this helps u out..

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3