Help please One-third x + one-sixth y = 2. When x is 3, 1 x + StartFraction 3 Over 6 EndFraction y = 6. One-half x + three-fourths y = negative 3. When x is negative 2, negative 1 x minus StartFraction 6 Over 4 EndFraction = 6. Negative 1 y = 12.
Continue solving the system of equations.

What is the solution to the system?

( , )

the answer to this question is 3/19

step-by-step explanation:

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation:

you just switch the numbers basically so it would be 3/17

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.