Atriangle has vertices at r(1, 1), s(–2, –4), and t(–3, –3). the triangle is transformed according to the rule r0, 270°. what are the coordinates of s'? (–4, 2) (–2, 4) (2, 4) (4, –2)

A. (-4,2)

Step-by-step explanation:

We are given that,

The vertices of the triangle are rotated about the origin by 270° counter-clockwise.

Thus, we get,

Vertices                         New vertices after 270° rotation

R= (1,1)                                              R' = (1,-1)

S= (-2,-4)                                          S' = (-4,2)

T= (-3,-3)                                          T' = (-3,3)

Thus, the co-ordinate of S' are (-4,2).

this doesn't make sense lol

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )