Line q passes through the point (4,6)and (0,6). What is the equation for the line which is parpendicular to q and passes through the point (-2,3)

The equation of the line passing through the points (4, 6) and (0, 6) will be:

The graph of the equation y = 6 is also attached.

Step-by-step explanation:

The slope-intercept form of the line equation

where

Given the points

Finding the slope between (4, 6)and (0, 6).

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

               =  [6 - 6] / [0 - 4]

               = 0 / -4  

               = 0

Thus, the slope of the line = m = 0

The slope m = 0 means the line is horizontal.  Because the slope of the horizontal line is 0.

As the y-values are not changing with respect to the x-values.

Therefore,

The equation of the line passing through the points (4, 6) and (0, 6) will be:

The graph of the equation y = 6 is also attached.

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

do i do it on a graph?

step-by-step explanation: