If point E is the midpoint of segment AC and point D is the midpoint of segment BC, which expression represents the value of s? triangle CAB, point E is on segment AC between points A and C and point D is on segment BC between points B and C, creating segment ED, CE equals p, EA equals r, CD equals q, DB equals t, ED equals s, and AB equals u s equals p over q s = one halfu s equals q over p s = 2u

The side ED is a midsegment of the triangle ΔABC, therefore, the length of

ED is half the length of AB.

Reasons:

The given parameters are;

In ΔABC, point E is the midpoint of AC

The midpoint of BC is the point D

Segment ED = s

Segment CE = p

Segment EA = r

Segment CD = q

Segment DB = t

Segment ED = s

Segment AB = u

Required;

The expression that represents the value of s

Solution:

CE = 0.5 × AC Definition of midpoint

CD = 0.5 × CB Definition of midpoint

Therefore;

Therefore, we have;

Therefore, given that ∠C ≅ ∠C, by reflexive property, we have;

ΔABC is similar to ΔCDE by Side-Angle-Side similarity

Which gives;

ED = s and AB = u which gives;

Which gives;

(The above relationship is given by the midsegment theorem)

Therefore;

The expression that represents the value of s is; s = one half u

Learn more about midsegment of a triangle here:

link

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

the answer is 2/54

step-by-step explanation: