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|y + 4| < 1
a.-5 < y < -3
b.-3 < y < 5
c.-4 < y < 1
d.1 < y < 4

|2t| - 5 + 7
a. t = 1 or -1
b. t = 6 or -6
c. t = 10 or -10
d. t = 12 or -12

|a| -3/4 = -5/8
a.1/8 or -1/8
b.7/8 or -7/8
c.1 3/8 or -1 3/8
d. no solution

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°