8 cars (3 red, 3 blue, 2 yellow) are parked in a line, how many arrangements can be formed if all the cars of each colour are identical and the yellow cars must not be together

the answer is 18. There are 18 ways to arrange the cars.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

answer: c. is your answer

step-by-step explanation: get me a black leather coat