All the students of the collage plays volleyball or cricket or both . if 70% plays volleyball and 65% plays cricket. what % of students plays volleyball only?

Let A and B represents the students play cricket and football respectively.

Let x be the percentage of students play neither cricket nor football.

Given:-

n(A∩B)=10

n(A)=50

n(B)=40

Now,

n(A)+n(B)+x−n(A∩B)=100

⇒50+40+x−10=100

⇒x=110−90=20

Hence 20% students play neither cricket not foot ball

Step-by-step explanation:

Hope it is helpful

it costs $20 to interview each person for a survey. find the cost to obtain a +- 3% margin of error.

step-by-step explanation:

copy and paste, put it in google

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0