You want to buy at most 6 articles of clothing. A clothing store sells shirts for $12 and pairs of pants for $18. You want to have at least $20 left over for food. Write a system of linear inequalities to represent the situation.

Complete question is;

You have $110 to spend at the mall. You want to buy at most 6 articles of clothing. A clothing store sells shirts for $12 and pairs of pants for $18. You want to have at least $20 left over for food. Write a system of linear inequalities to represent the situation.

x + y ≥ 6

110 - (12x + 18y) ≥ 20

Step-by-step explanation:

Let x represent number of shirts

Let y represent number of pairs of pants.

You want to buy at most 6 articles of clothing.

Thus;

x + y ≥ 6

A clothing store sells shirts for $12 and pairs of pants for $18. You want to have at least $20 left over for food.

Thus;

110 - (12x + 18y) ≥ 20

2500

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)