What is the equation of the line that has a slope of 1/3 and goes through the point (6,−2)? A. y = 1/3x − 4
B. y = 1/3x + 4
C. y = 1/3x − 8
D. y = 1/3x

A) y = 1/3x − 4

Step-by-step explanation:

Find the Equation Using Point-Slope Formula

slope: 1/3

point: (6, −2)

Use the slope 1 and a given point (6, −2) to substitute for  and  in the point-slope form  

y - = m(x - ), which is derived from the slope equation m =

  y − (−2) = 1/3 ⋅ (x − (6))

Simplify the equation and keep it in point-slope form.

  y + 2 = 1/3 ⋅ (x − 6)

Solve for y.  

  1/3 ⋅ (x − 6).

Apply the distributive property.

  y + 2 =  1 /3 x +  1 /3 ⋅ − 6

Combine 1/3 and x.

  y + 2 =  x/3 +1/3 ⋅ −6

Cancel the common factor of 3.

  y + 2 =  x /3 − 2

Move all terms not containing y to the right side of the equation.

Subtract 2 from both sides of the equation.

  y = x/3 − 2 − 2

Subtract 2 from −2. x

  y = x/3 − 4

Reorder terms.

  y = 1/3x − 4

List the equation in different forms.

Slope-intercept form:  

y = 1/3x − 4

Point-slope form:

y + 2 = 1/3 ⋅ (x − 6)

853.3

step-by-step explanation:

126 maybe. sorry