A bag has one red ball, three blue balls and twice as many green balls as blue balls. if one ball is drawn (without looking) from the bag what are the chances that the ball will be blue?

3/10 or three tenths or 0.3 or 0.30

Step-by-step explanation:

Plz brainliest

30% or 3/10

Step-by-step explanation:

First you need to figure out how many balls are in the bag. There is 1 red, 3 blue, and 2x (x=# of blue balls) green balls. since there is 3 blue balls you double 3 to get how many green balls there are, which is 6. Then you do 1+3+6 to give you 10. Since there is 3 blue balls in a bag that consists of 10 balls, you have a probability of 3/10 or 30% or .3 to draw a blue ball.

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !