CL 3-115. Jermaine has a triangle with sides 8, 14, and 20. Sadio and Aisha both think that they have triangles that are similar to Jermaine's triangle. The sides of Sadie's triangle are 2, 3.5, and 5. The sides of Aisha's triangle are 4, 10, and 16. Decide who, if anyone, has a triangle similar to Jermaine's triangle. Be sure to explain how
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CL 3-116. For the points R(-2, 7) and P(2,1) determine each of the following:

9514 1404 393

  Jermaine and Sadie have similar triangles. Aisha's is not similar.

Step-by-step explanation:

The side lengths can be arranged smallest-to-largest and reduced to mutually-prime integers. If the triangles are similar, their side ratios will be the same.

  Jermaine's triangle has side ratios ...

     8 : 14 : 20 = 4 : 7 : 10

  Sadie's triangle has side ratios ...

     2 : 3.5 : 5 = 4 : 7 : 10 . . . . (same as Jermaine's)

  Aisha's triangle has side ratios ...

     4 : 10 : 16 = 2 : 5 : 8 . . . . . (different from Jermaine's)

Sadie and Jermaine have similar triangles.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.