Find the equation of the perpendicular line to 2x-5y-10=0 and containing point (-1,5)

y = -2.5x + 2.5

Step-by-step explanation:

Put the equation into y = mx + b form by isolating y:

2x - 5y - 10 = 0

2x - 5y = 10

-5y = -2x + 10

y = 2/5x - 2

Perpendicular lines have opposite reciprocal slopes, so the line's slope will be -5/2, or -2.5

Plug in the slope and given point into y = mx + b, and solve for b:

y = mx + b

5 = -2.5(-1) + b

5 = 2.5 + b

2.5 = b

Plug in the slope and y intercept:

y = mx + b

y = -2.5x + 2.5 is the equation of the perpendicular line

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