Question 4 10 pts
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Question 8
What is the length of line segment DK to the nearest tenth of an inch?
Time Running Hide
1 Hour, 26 Minutes, 25 Sec
16 in
430
D
O 10.9 in
0 21.9 in
O 23.5 in.
O 11.7 in.
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C = 23.5 in

Step-by-step explanation:

θ = 43°

The length of the side opposite to θ = 16 in.

Hypotenuse = DK

Apply trigonometric ratio, thus:

sin(θ) = opp/hyp

Plug in the values

sin 43 = 16/DK

Multiply both sides by DK

DK*sin 43 = 16

Divide both sides by sin 43

DK = 16/sin 43

DK = 23.5 (nearest tenth of an inch)

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