A repairman charges an inspection fee plus $22 per hour. A customer with a coupon for 40% off the inspection fee pays $118 for a 4-hour repair. How many hours are worked when a customer pays $94 without a coupon?

Inspection fee = $50

h = 2 hours

Step-by-step explanation:

Let

x = the inspection fee

Charge per hour = $22

Number of hours = 4

A customer with a coupon for 40% off the inspection fee

This means the customer paid 60% of the inspection fee

118 = 60% of x + 22(4)

118 = 0.6x + 88

118 - 88 = .6x

30 = .6x

x = 30/0.6

x = $50

Inspection fee = x = $50

How many hours are worked when a customer pays $94 without a coupon?

94 = 50 + 22h

94 - 50 = 22h

44 = 22h

h = 44/22

h = 2 hours

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)