An information technology company produces 45% of its computer chips at a plant in St. Louis and the remainder of its chips at a plant in Chicago. It is known that 0.85% of the chips produced in St. Louis are defective, while 1.05% of the chips produced at the plan in Chicago are defective. What is the probability that a randomly chosen computer chip produced by this company is defective and was produced in St. Louis?

the probability of the computer chip produced and defective is 0.003825

Step-by-step explanation:

The computation of the probability of the computer chip produced and defective is shown below

= Produced percentage × defective percentage

= 45% × 0.85%

= 0.003825

Hence, the probability of the computer chip produced and defective is 0.003825

The same is considered and relevant too

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)