A die is rolled 25 times and 12 evens are observed. Calculate and interpret a 95% confidence interval to estimate the true proportion of evens rolled on a die.

The 95% confidence interval to estimate the true proportion of evens rolled on a die is (0.2842, 0.6758). This means that we are 95% sure that for the entire population of dies, the true proportion of evens rolled on a die is between 0.2842 and 0.6758

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

For this problem, we have that:

95% confidence level

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval to estimate the true proportion of evens rolled on a die is (0.2842, 0.6758). This means that we are 95% sure that for the entire population of dies, the true proportion of evens rolled on a die is between 0.2842 and 0.6758

your answer would be 10x - 1

is only a line? i think so