Solve the system of linear equations by elimination. 10x-9y=46 and -2x+3y=10

y=16 and x=19

Step-by-step explanation:

Let's solve your system by elimination.

−2x+3y=10;10x−9y=46

Multiply the first equation by 5,and multiply the second equation by 1.

5(−2x+3y=10)

1(10x−9y=46)

Becomes:

−10x+15y=50

10x−9y=46

Add these equations to eliminate x:

6y=96

Then solve6y=96for y:

6y=96

6y

6

=

96

6

(Divide both sides by 6)

y=16

Write down an original equation:

−2x+3y=10

Substitute16foryin−2x+3y=10:

−2x+(3)(16)=10

−2x+48=10(Simplify both sides of the equation)

−2x+48+−48=10+−48(Add -48 to both sides)

−2x=−38

−2x

−2

=

−38

−2

(Divide both sides by -2)

x=19

x=19 and y=16

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.