Find the equation of the line
passing through the points (5, 2)
and (10, 6).
y =
Xt

y=4/5x-2

Step-by-step explanation:

here are the given points: (5,2) and (10,6)

First, let's find the slope, which is found with the equation (y2-y1)/(x2-x1)

so let's label the points

x1=5

y1=2

x2=10

y2=6

now we can substitute into the equation

m=(6-2)/(10-5)

subtract

m=4/5

so that means the slope is 4/5

Now, let's use point slope form, which is y-y1=m(x-x1) (m is the slope)

so let's substitute the numbers we know from earlier into the equation

y-2=4/5(x-5)

do distributive prop.

y-2=4/5x-4

add 2 to both sides

y=4/5x-2

hope this helps!

1 3 5

step-by-step explanation:

i took the test: )