Find the equation of the line that is perpendicular to y=-2/3x and contains the point (4 -8)

y = 3/2x + -14

Step-by-step explanation:

y = -2/3 x

has a slope of -2/3

We want a line perpendicular

Take the negative reciprocal to find the slope

- (1 / -2/3)

3/2

The slope of a line perpendicular is 3/2

Using the slope intercept form of a line

y = mx+b  where m is the slope and b is the y intercept

y = 3/2x +b

Substitute a point into the equation

-8 = 3/2(4) +b

-8= 6+b

Subtract 6 from each side

-8-6 = b

y = 3/2x + -14

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

[2, 2.5)

(2.5, 3]

step-by-step explanation:

i think its these two not sure [2, 2.5)

(2.5, 3]