Find JK if KF= 1 *No A-D options(write the answer)

The length of JF = 3

Step-by-step explanation:

We know that the point of intersection of the Medians of a triangle is called the centroid of a triangle.

Thus,

For the given triangle ΔHIJ,

We also know that the centroid is 2/3 of the distance from each vertex to the midpoint of the opposite side.

Also, each Median is split into two parts such that the longer part is 2 times the length of the smaller part.

In our case,

The median JF is split into two parts such that the longer part JK is 2 times the length of the smaller part KF.

In other words,

JF = KF + JK

Given KF = 1

Also, the longer part JK is 2 times the length of the smaller part KF.

i.e.

JK = 2 KF

JK = 2(1)         ∵ KF = 1

JK = 2

Thus, substituting KF = 1 and JK = 2 in JF = KF + JK

JF = KF + JK

JF = 1 + 2

JF = 3

Therefore, the length of JF = 3

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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step-by-step explanation: