What is the standard form of (6x^2-8x-7)+(8x^2-76x)

 14x^2 - 84x - 7

Explanation:

The like terms 6x^2 and 8x^2 combine to 14x^2

The like terms -8x and -76x combine to -84x

Nothing pairs with the -7, so its stays as is.

Standard form is where we list the terms in decreasing exponent order. We can think of -84x as -84x^1 and the -7 as -7x^0. So 14x^2 - 84x - 7 would be the same as 14x^2 - 84x^1 - 7x^0. The exponents count down: 2,1,0.

The final answer is a trinomial since it has three terms. It is also a quadratic because the degree (highest exponent) is 2.

sorry, can't i suggest going to algebra.com

step-by-step explanation:

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.