Find the 6th term of an arithmetic sequence given that a(1)= 12 and a(n)= a(n-1)-23

-103

Step-by-step explanation:

a(1) = 12

a(n) = a(n-1) - 23

a(2) = a(1) - 23

       = 12 - 23

      = -11

Common difference (d) = a(2) -a(1) = -11 - 12  = -23

a(n) =  a1 + (n-1)d

a(6) = 12 + 5 * (-23)

       = 12 - 115

       = -103

answer: 0,6

step-by-step explanation:

this would make it the y intercept.