Please help will give and all my points but please show work

Q10: 5x - 3

Q15: s = 2

Q21: 4 ft

Q24: -33%

Q42: 10.3

Step-by-step explanation:

Question 10) Simplify. 5 + 2(3x − 4) − x

5 + 6x - 8 - x

= -3 + 5x

= 5x -3

Question 15) Solve. 27s − 29 = 54s − 83.

27 s -27 s -29 + 83 = 54 s -27 s -83 + 83

54 = 27 s

s = 2

Question 21) On a sunny day, a 2-foot red kangaroo casts a shadow that is 7 feet long. The shadow of a nearby eucalyptus tree is 14 feet long. Find the height of the tree.

The ratio of the tree and kangaroo is 2:1

Therefore, using this logic, 14 / 7 = 2, 2 x 2 = 4ft

The height of the tree is 4ft

Question 24) Find the percent change from 600 to 408. Tell whether it is a percent increase or decrease. If necessary, round your answer to the nearest percent.

408 / 608 = 0.67 = 67%

67 - 100 = -33%

This is a percent decrease

Question 42) Use the distance formula to find the distance to the nearest tenth, from R(7, −2) to W(−2, 3).

Distance formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

d = sqrt((-2 - 7)^2 + ( 3 - (-2))^2

d = sqrt((-9)^2 + (5)^2)

d = sqrt(81 + 25)

d = sqrt(106)

d = 10.29 = 10.3 (nearest tenth)

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: