Math problem\James and lucas committed in a climbing competition and coming back down. James climbed at the average 3 mph and came back down at 4 mph. Lucas climb at the average of 2 mph and came back down at 5 mph. If the path from the bottom to the top was 2 miles how much time did it take for both friends to finish and who was faster.

1.166666 ; 1.4 ; James

Step-by-step explanation:

Given that:

Path from bottom to top = distance = 2 miles

Time taken = distance /speed

James :

To climb up:

Time = 2 / 3 = 2/3 hours

Coming down :

Time = 2 / 4 = 1/2 hours

Total time taken = 2/3 + 1/2 = 1.166666 hours

1.166666 * 60 = 70 minutes

Lucas :

To climb up:

Time = 2 / 2 = 1 hour

Coming down :

Time = 2 / 5 = 2/5 hours

Total time taken = 2/3 + 1/2 = 1.4 hours

1.4 * 60 = 84 minutes

James was faster :

1.166666 < 1.4

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )