What is the value of cos if the terminal side is the line 3x - 4y = 0, x < 0 4/5
3/5
-4/5
-3/5

throw the computer

step-by-step explanation:

idk

step-by-step explanation:

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.