Mathematics, 18.01.2021 06:00 luis173506

On a coordinate grid, a grocery store is located at (3,0) and the hardware store is located at (4,3). If the hardware store is the midpoint between the
grocery store and the pharmacy, what is the approximate distance from
the hardware store to the pharmacy? (Note: 1 unit equals 5 miles) *
7.5 miles
15.8 miles
O 79 miles
O 17.5 miles

Answers: 2

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Answers

Answer from: emma3216

Hence the required distance is 6.32 units.

Step-by-step explanation:

Given that , On a coordinate grid, a grocery store is located at (3,0) and the hardware store is located at (4,3). If the hardware store is the midpoint between the grocery store and the pharmacy .

And we need to find approximate distance from

the hardware store to the pharmacy .

Coordinate of hardware = (4,3)Coordinate of grocery = ( 3, 0)Coordinate of pharmacy = (x , y) [ Let ] Using Midpoint formula ,

⇒ Midpoint = ( x1 + x2 )/2 , (y1 + y2 )/2

⇒ 4,3 = (3+x)/2 , (y+0)/2

⇒ 4,3 = (3+x)/2 , y/2

⇒ 4 = 3+x/2

⇒ 3+x = 8

⇒ x = 8-3

⇒ x = 5

⇒ y/2 = 3

⇒ y = 3*2

⇒ y = 6

Hence the coordinate of pharmacy is (5,6)

Using Distance Formula ,

⇒ Distance = √ [ (x2 -x1 )² + (y2 - y2)² ]

⇒Distance = √ [ (5-3)² + (6-0)² ]

⇒ Distance = √ [ 2² + 6² ]

⇒ Distance= √ 4 + 36

⇒ Distance = √ 40

⇒ Distance = 6.32 units

Answer from: Quest

- 2 $x^{4}$ + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 $x^{4}$ + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 $x^{4}$ + 10x³ - 21x² + 19x - 4 ← in standard form

Answer from: Quest

the system of inequalities is

$y> (1/3)x$

$y\leq-x+4$

step-by-step explanation:

step 1

find the equation of the dashed line

we have the points

(0,0) and (3,1)

the line passes through the origin, so, is a direct variation

find the slope

$m=y/x=1/3$

the equation of the dashed line is

$y=(1/3)x$

the solution of the inequality a s the shaded area above the dashed line

therefore

the equation of the inequality a is

$y> (1/3)x$

step 2

find the equation of the solid line

we have the points

(4,0) and (0,4)

find the slope

$m=(4-0)/(0-4)=-1$

the equation of the solid line is

$y=-x+4$

the solution of the inequality b s the shaded area below the solid line

therefore

the equation of the inequality b is

$y\leq-x+4$

step 3

the system of inequalities is

$y> (1/3)x$

$y\leq-x+4$

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