Sweety’s mother is 12 years more than twice Sweety’s age. After 8 years, she will be 20 years less than three times Sweety’s age. Find Sweety’s age and Sweety’s mother’s age?

Sweety's age = 16 years and  Sweety’s mother’s age = 44 years

Step-by-step explanation:

Let Sweety's age is x.

Sweety’s mother age = 12+2x

After 8 years,

Sweety's age = x+8

Sweety’s mother age = 12+2x+8

Since Mother's age will be 20 years less than three times my age.

2x+20 = 3(x+8)-20

2x+20=3x+24-20

2x+20=3x+4

Taking like terms together,

20-4=3x-2x

x = 16

Sweety's age = 16 years

Sweety’s mother’s age = 12+2x

= 12+2(16)

= 12 + 32

= 44 years

Hence, Sweety’s age and Sweety’s mother’s age is 16 years and 44 years respectively.

3x^3-x^2+6x-9

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation: