Help i cant figure this equation out 9x-7i 3(3x-7u)

49i^3u−21i^3x+9x

Step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

i believe the answer is c.