The diagram shows information about the final 70 seconds of a car journey. (a) Find the deceleration of the car between 60 and 70 seconds.

I have attached an image showing the diagram.

-2 m/s²

Step-by-step explanation:

From the diagram, in decelerating from between 60 to 70 seconds, it moved from a velocity of 20 m/s to 0 m/s.

Thus, using Newton's first equation of motion, we can find the deceleration;

a = (v - u)/t

Time (t) = 70 - 60 = 10 s

Final velocity (v) = 0 m/s

Initial velocity (u) = 20 m/s

Thus;

a = (0 - 20)/10

a = -20/10

a = -2 m/s²

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

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