Here are the first five terms of an arithmetic sequence. 26 19 12 5
(b) Find an expression, in terms of n, for the nth term of this sequence.

The nth term of an AP will be 27 -7n.

Step-by-step explanation:

First five terms of the Arthemetic Sequence is given to us , which is 26 , 19 , 12 , 5

Hence here Common Difference can be found by subtracting two consecutive terms . Here which is 19 - 26 = (-7) .

Here first term is 26 .

And the nth term of an AP is given by ,

★ T_n = a + ( n - 1) d

Substituting respective values ,

⇒ T_n = a + ( n - 1 )d

⇒ T_n = 26 + (n - 1)(-7)

⇒ T_n = 26 -7n+1

⇒ T_n = 27 - 7n

your answer   is c

step-by-step explanation:

let f (x ) is a function and c be a positive real number,   the graph of the function g (x ) = f (cx ) is represented as follows.

when, c > 1,   the function compresses it in the x - direction.

when, 0 < c < 1, the function stretches it.

the function is g ( x ) = (9x )2.

the heighest power of x in g ( x ) = (9x )2 is 2, so the parent function is square function.

the equation of parent function is f ( x ) = x 2 .

the function is g ( x ) = (9x )2 and the parent function is f ( x ) = x 2 .

so, the functions f and g have the following relationship.

g ( x ) = f ( 9x ).

compare the function g ( x ) = f ( 9x ) with g (x ) = f (cx ).

c = 9 ( > 1 ).

so, the function g (x ) = (9x )2 compresses it in the x - direction.

step-by-step explanation: