A boat is pulled into a dock by a rope with one end attached to the front of the boat and the other end passing through a ring attached to the dock at a point 5 feet higher than the front of the boat. The rope is being pulled through the ring at the rate of 0.6 ft/sec. How fast is the boat approaching the dock when 13 feet of rope are out

The boat is approaching the dock  at 0.65 ft/sec when 13 feet of rope are out.

Step-by-step explanation:

Let x be the length of rope and y be the distance between boat and dock.

Height of point where a ring attached =z=5 feet

x=13 feet

Using Pythagoras theorem

Differentiate w.r.t t

Hence,the boat is approaching the dock  at 0.65 ft/sec when 13 feet of rope are out.

answer: 91

step-by-step explanation:

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.