Find the equation of parallel line and perpendicular line .

Part 1)

The slope-intercept form of the line equation

where m is the slope and b is the y-intercept

Given the equation

comparing with the slope-intercept form of the line equation y = 3x-4

Thus, the slope of the line: m = 3

We know that the parallel lines have the same slopes.

Thus, the slope of the paralellel line is also: 3

substituting the slope m = 3 and the point (5, -3) in the slope-intercept form

-3 = 3(5) + b

-3 = 15 + b

b = -3-15

b = -18

Therefore, the value of y-intercept b = -18

now substituting the slope m = 3 and the y-intercept b = -18 in the slope-intercept form

y = 3x + (-18)

y = 3x - 18

Therefore, the equation of line parallel to the given line will be:

Part 2)

The slope-intercept form of the line equation

where m is the slope and b is the y-intercept

Given the equation

comparing with the slope-intercept form of the line equation y = 3x-4

Thus, the slope of the line: m = 3

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:  

slope = m = 3

Thus, the slope of the the new perpendicular line = – 1/m = -1/3 = -1/3

substituting m = -1/3 and the point   (5, -3)  in the slope-intercept form

now substituting the slope m = -1/3 and the y-intercept b = -4/3 in the slope-intercept form

Therefore, the equation of the line perpendicular to the given line will be:

multiple all that

step-by-step explanation:

27×17

i have no idea just need points sorry

step-by-step explanation: