Three pollsters will canvas a neighborhood with 21 houses. Each pollster will visit seven of the houses. How many different assignments of pollsters to houses are possible

116,280 assignments

Step-by-step explanation:

We would solve this question using the combination formula

This is given as:

C(n, r) = nCr = n!/n! (n - r)!

Where

n = 21

r = 7

Hence:

21C7 = 21!/7! × (21 - 7)!

= 21!/7! × 14!

= 116,280 assignments

Therefore, the number of different assignments of pollsters to houses that are possible are 116,280 assignments

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents