A military plane is flying directly toward an air traffic control tower, maintaining an altitude of 9 miles above the tower. The radar detects that the distance between the plane and the tower is 15 miles and that it is decreasing at a rate of 750mph. What is the ground speed of the plane

-937.5 mph

Step-by-step explanation:

Assuming this takes place in a right angled triangle. With the hypotenuse side being, d, 15 miles, the opposite side being 9 miles and the adjacent being an unknown, x.

Using Pythagoras theorem, we know that

x² = 15² - 9²

x² = 225 - 81

x² = 144

x = √144

x = 12 miles.

Again, we should know that

2xx' = 2dd', this means that

xx' = dd'

From the question, we're told that it's decreasing at d' = 750 mph. On substituting, we have

x' = dd' / x

x' = (15 * -750) / 12

x' = -11250 / 12

x' = -937.5 mile per hour

The ground speed of the plane is also decreasing at 937.5 mile per hour

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step-by-step explanation:

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right