Given a Rhombus with diagonals of 70 inches and 24 inches, what is the perimeter of the Rhombus?

148 inches

Step-by-step explanation:

1. You would want to split the rhombus into 4 right triangles.

2. You know two sides of the right triangles (One side would be 12 inches and the other 35) Knowing that you would use the Pythagorean theorem.

3. 35^{2}+12^{2}=c^{2}

4. Solve: 1225 + 144 = 1369

5. The square root of 1369 is 37

6. Multiply 37 x 4 (For all the sides of your triangles)

7. 148 inches

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )