Solve the following systems of equations by elimination

- 2x - 5y=-27
- 2x + 3y = 13

x= 1

y- 5

Step-by-step explanation:

okay so you know the rules...

we need to eliminate one variable to solve this system so first...

im going to get rid of x first to do so i need to...

multiply any of the equation by negative one to get it to a positive to eliminate

-2x - 5y= -27

( -2x + 3y= 13) -1

-2x -5y= -27

2x -3y= -13   follow the rules of signed integers

we eliminate x and have this left

-5y= -27

-3y= -13    use the second rule of eliminationadd the rest up

-8y= -40   divide both sides by -8

y= 5

we arent done yet we need to find the other variable

plug in y to one of the equations like this...

-2x - 5(5)= -27

-2x - 25= -27   add -25 to both sides to get the variable by itself

-2x= -2   divide both sides by -2

x= 1

Hope this helped!

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

a

step-by-step explanation:

the answer is a