Find the equation of the line Which passes through ( -4,-2) and it is parallel to 2y-6x-3 =0

y = 3x + 10

Step-by-step explanation:

In this question, we have to find an equation of a line that's parallel to the equation given.

First, lets turn the given equation into slope-intercept form:

2y - 6x - 3 = 0

Add 6x and 3 to both sides.

2y = 6x + 3

Divide both sides by 2.

y = 3x + 3/2

We know that the slope of our parallel line has to be 3, now we just need to find what our beginning point, or y-intercept, is.

To find our parallel line, plug in the coordinates to the y = 3x + b and solve.

Solve for b:

-2 = 3(-4) + b

-2 = -12 + b

Add 12 to both sides.

10 = b

Our parallel equation would be: y = 3x + 10

10

step-by-step explanation:

7+3=10

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0