Find an equation for the perpendicular bisector of the line segment whose endpoints are (5,-2) and (-1,-6)

y = -3x/2 - 15/2

Step-by-step explanation:

The equation of a line is expressed as y = mx+c

m is the slope

y is the y-intercept

Get the slope;

m = -6+2/-1-5

m = -4/-6

m = 2/3

m = -1/2/3 = -3/2 (since the line is a perpendicular bisector)

Get the equation of the line

y -(-6) = -3/2(x-(-1))

y+6 = -3/2(x+1)

2(y+6) = -3(x+1)

2y+12 = -3x - 3

2y = -3x -15

y = -3x/2 - 15/2

Hence equation for the perpendicular bisector of the line segment whose endpoints are (5,-2) and (-1,-6) is y = -3x/2 - 15/2

1,8,15,22,29,36,43,50

step-by-step explanation: