Find the zeros of y = x2 – 6x – 4 by completing the square.

The solutions to the quadratic equations are:

Step-by-step explanation:

Given the function

substitute y = 0 in the equation to determine the zeros

Switch sides

Add 4 to both sides

Simplify

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

Apply perfect square formula:  (a-b)² = a²-2ab+b²

solve

Add 3 to both sides

Simplify

now solving

Add 3 to both sides

Simplify

Thus, the solutions to the quadratic equations are:

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.

im not sure what this means: mc011-7.jpg

step-by-step explanation: