How do you solve this equation ? solving simultaneous equations by substitution
9x - 2y = -1
2y = 3x - 5

x= -1

y= -4

Step-by-step explanation:

9x-2y= -1equation 1

2y= 3x-5equation 2

From equation 2

2y= 3x -5

y= 3x-5/2

Substitute 3x-5/2 for y in equation 1

9x -2(3x-5/2)= -1

9x -(3x-5)= -1

9x -3x+5= -1

6x= -1-5

6x= -6

x= -6/6

x= -1

Substitite -1 for x in equation 2

2y= 3(-1)-5

2y = -3-5

2y = -8

y = -8/2

y= -4

Hence x = -1 and y= -4

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)