1. A box contains 10 blue Stickers, 15 red stickers , and 25 orange stickers . A sticker is selected and its color noted. Then it is replaced. A second sticker is selected and its color noted. Find the probability of each of these. a. Selecting blue and blue stickers
b. Selecting one red sticker and then one orange sticker
c. Selecting one red sticker and then one blue stickers

1/25 ; 3/20 ; 3/50

Step-by-step explanation:

Total number of stickers :

(10 + 15 + 25) = 50 stickers

Probability = required outcome / Total possible outcomes

a. Selecting blue and blue stickers

P(First blue) = 10/50 = 1/5

P(second blue) = 10/50 = 1/5

1/5 * 1/5 = 1 / 25

b. Selecting one red sticker and then one orange sticker

P(First red) = 15/50 = 3/10

P(second orange) = 25/50 = 1/2

3/10 * 1/2 = 3 /20

Selecting one red sticker and then one blue sticker

P(First red) = 15/50 = 3/10

P(second blue) = 10/50 = 1/5

3/10 * 1/5 = 3 / 50

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

step-by-step explanation: