In triangle ABC above, AD is perpendicular to CB. If the lengths of AD and CB were both increased by 50%, how would the area of ABC change?

The answer is below

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as scalene triangle, equilateral triangle, isosceles triangle.

The area of a triangle is given as:

A = (1/2) * b * h

where b = base of triangle, h = height of triangle , A = area

Let BC = base = x, and AD = height = y, hence:

A = (1/2) * x * y = 0.5xy

If the lengths of AD and CB were both increased by 50%, hence:

new AD = y + 0.5y = 1.5y, new CB = x + 0.5x = 1.5x

The new area= (1/2) * 1.5y * 1.5x = 1.125xy

Increased area / area = 1.125xy / 0.5xy = 2.25

If the lengths are increased by 50%, the area would also increase and the new area would be 2.25 times

a. is correct