The distances (in yards) for nine holes of a golf course are listed. 336 393 408 522 147 504 177 375 360
(a) Find the mean and the median of the data.
(b) Convert the distances to feet. Then rework part (a).
(c) Compare the measures you found in part (b) with those found in part (a). What do you notice?
(d) Use your results from part (c) to explain how to quickly find the mean and the median of the original data set when the distances are converted to inches.

A.) 358; 375

B.) 1074 ; 1125

C.) Both the mean and median values in feets could be obtained by just multiplying the values in yards by 3

D.) If we have our median and mean of thee original dataset in inches, we just divide the values by 36 to get our mean and median values in yard.

Step-by-step explanation:

Given the data (in yards)

Rearranged data : x (in yards) :

441, 531, 1008, 1080, 1125, 1179, 1224, 1512, 1566

Mean, m : Σx/n

ΣX = 3222 ; n = sample size, n = 9

m = 3222 / 9

m = 358

Median :

0.5(n +1) th term

0.5(9 + 1)th term

0.5(10) = 5th term = 375

Converting the data to feets :

147, 177, 336, 360, 375, 393, 408, 504, 522

1 yard = 3 feets

In Feets:

441, 531, 1008, 1080, 1125, 1179, 1224, 1512, 1566

Mean, m : Σx/n

ΣX = 9666 ; n = sample size, n = 9

m = 9666 / 9

m = 1074

Median :

0.5(n +1) th term

0.5(9 + 1)th term

0.5(10) = 5th term = 1125

C) Both the mean and median values in feets could be obtained by just multiplying the values in yards by 3

D.) since 1 yard = 36 inches

If we have our median and mean of thee original dataset in inches, we just divide the values by 36 to get our mean and median values in yard.

i think the answer is b.

step-by-step explanation:

not 100% sure though.